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=5Y^2-60Y+166
We move all terms to the left:
-(5Y^2-60Y+166)=0
We get rid of parentheses
-5Y^2+60Y-166=0
a = -5; b = 60; c = -166;
Δ = b2-4ac
Δ = 602-4·(-5)·(-166)
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{70}}{2*-5}=\frac{-60-2\sqrt{70}}{-10} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{70}}{2*-5}=\frac{-60+2\sqrt{70}}{-10} $
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